Talk:Mitchell Gore/Sandbox 3
Jump to navigation
Jump to search
Math display issue[edit source]
H = \frac {1}{2\tan\theta} \cdot P = \frac {\sqrt 3}{2}\cdot P \approx 0.866 \cdot P</math>
H = \frac {1}{2\tan\theta} \cdot P = \frac {\sqrt 3}{2}\cdot P \approx 0.866 \cdot P</math>